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Data Interpretation for Bank Exams 2017 – SBI, IBPS

Data Interpretation for Bank Exams 2017

Data Interpretation is the very important topic for SBI and IBPS PO Exams. We need to learn some shortcut methods in adding, subtracting, multiplication and speed maths tricks on some Quantitative aptitude topics to solve Data Interpretation questions in less time.




Directions: Study the following graphs carefully and answer the following questions given below in each graph.

I. Data Interpretation Practice Problem 1:       

Number of candidates (boys and girls) appeared and qualified in an examination over the years

(1.1) What was the approximate percentage of boys qualified to appeared in 1992?

(A) 35             (B) 70                    (C) 80                    (D) 65

 

Solution 🙁 B)  The approximate percentage of boys qualified to appear in 1992.

                                                                             =12.5/17.5 × 100=71.43  = 70%

(1.2) The total number of girls qualified in 1991 and 1992 together was exactly equal to the number of girls appeared in which of the following years—

(A)    1994                       (B)    1995             (C)   1991              (D) 1990               (E) none of these

 

Solution 🙁 d)    The total number of girls qualified to appear in 1991 and 92.

                                                                                =2500+5000= 7500

                                                                                = Total number of girls involved is 1990

(1.3) What was the percentage increase in the number of boys qualified from 1993 to 1994?

(A) 50                (B) 5                       (C) 100                  (D) 200                  (E) none of these

 

Solution 🙁 d)    The percentage increase in the number of boys qualified from 1993 to 1994

                                                                                = (15 – 5) * 1000=10000

                                   Percentage increase = 10000/5000* 100 = 200

(1.4) What did the difference between the total number of boys and girls appeared in 1993 and the total number of boys and girls appear in 1991?

(A) 500               (B) 2500                (C) 7500                (D) 10000             (E) none of these

Solution 🙁 b)    difference between the total number of boys and girls appeared is 1993 and the total number of boys and girls appeared is 1993 and the total number of boys and girls appeared in 1991

                                                                                = [(12.5 + 10) – (15 + 5)] * 1000

                                                                                = (22.5 – 20) * 1000= 2.5* 1000

                                                                                = 2500

(1.5) In which of the following year was the percentage of girls qualified to appear the highest among the given years?

(A) 1991              (B) 1993                (C) 1994                (D) 1992               (E) none of these

 

Solution 🙁 b)    the percentage of girls qualified to appear in 1990      = 5.0/7.5×100 = 66.66%

                             The percentage of girls qualified to appear in 1991      = 2.5/5×100 = 50%

                            The percentage of girls qualified to appear in 1992      = 5/10×100 = 50%

                                The percentage of girls qualified to appear in 1993     = 7.5/10×100 = 75%

                                The percentage of girls qualified to appear in 1995     = 7.5/12.5×100 = 60%

                                The percentage of girls qualified to appear in 1996     =  12.5/17.5×100 = 71.43%

 

DI Practice Problem II:

Percentage profit earned by two companies over the given years.

% Profit = [(Income –Expenditure)/ Expenditure]*100.

 

 


 2.1 ) If the expenditure of the company B in 2008 was Rs.200 crores. What was the income?

  1. 240 Crores
  2. 220 Crores
  3. 160 Crores
  4. Cannot be determined
  5. None of these.

Let the income be Rs. X Crores.

20 = [(x-200)/200] × 100

  • 40 = x-200
  • X=Rs. 240 crores.

 

2.2) If the income of Company A in 2010 was Rs.600 crores, what was its expenditure?

  1. 360 crores.
  2. 480 Crores.
  3. 375 Crores.
  4. Cannot be determined
  5. None of these

The income of Company A in 2002 is Rs. 600 crores and % profit = 60
Assume expenditure is x.
60 = [(600 – x)/x] ×100
x= [(600 – x)/ 60 ] × 100
3x = 3000 – 5x
8x = 3000
X = Rs. 375 Crores

2.3) If the income of company B in 2006 was Rs.200 crores. What was its profit in 2007?

  1. 21.5 Crores
  2. 153 Crores
  3. 46.15 Crores
  4. Cannot be determined (income and expenditure not given in 2007)
  5. None of these.

2.4) If the income of the two companies in 2006 were equal, what was the ratio of their expenditure?

  1. 1: 2
  2. 26: 27
  3. 100:67
  4. Can’t solve
  5. None of these.

Company A, 35 = [(I – Exp1)/Exp1 ] × 100   -> (1)

  • 35Exp1 = 100 I – 100 Exp1
  • 135 Exp1 = 100 I

Company B, 30 = [(I – Exp2)/Exp2 ] × 100  

130 Exp2 = 100 I  -> (2)
From (1) and (2)
135 Exp1 = 130 Exp2
Exp1/Exp2 = 130/135
Ratio of Expenditures of A and B ,
Exp1: Exp2 = 130 : 135
26: 27.

2.5) What is the percent increase in percent profit for company B from the year 2008 to 2009?

  1. 75
  2. 175
  3. 86
  4. Cannot be determined

= [(35- 20)/ 20 ] × 100  = 75

DI Practice Problem III:

Percent Profit earned by two companies producing Electronic Goods over the years.
Profit Earned = Total Income – Total Investment in the year.

3.1) If the profit earned in 2006 by company B was Rs. 812500. What was the total income of the company in that year?
(a) Rs. 12, 50, 000
(b) Rs. 20, 62, 500
(c ) Rs. 16, 50, 000
(d ) Rs. 18, 25, 000
Sol: 
% profit = [profit earned / total investment ] × 100
65 = [812500/ 1 ] × 100
I = (812500 × 100)/65
  = Rs. 1250000
Total Income = Profit earned  + total investment.
= Rs. (812500 + 1250000)
= Rs. 2062500

3.2) If the amount invested by two companies in 2005 was equal, what was the ratio between the total income in 2005 of the companies A and B respectively?
(a) 31: 33
(b) 33: 31
(c ) 34: 31
(d ) 14: 11
Sol: 
70 = (x/ I)  × 100

  • 70 I = 100x  —–à (1)

 55 = (y/ I)  × 100

  • 55 I = 100y  —–à (2)

From (1) & (2 )

 [70 I /100 ] +I : [ 55 I/ 100] +I

170 I : 155 I  = 34 : 31.

3.3) If the total income invested by two companies in 2009 was Rs. 27 lakhs while the amount invested by company B  was 50% of the amount invested by company A. What was the total profit earned by the two companies together?
(a) Rs. 21.15 lakhs
(b) Rs. 20.70 lakhs
(c ) Rs. 18.70 lakhs
(d ) Rs. 20.15 lakhs

Sol.: 
Investment by company A = [2/3] × 27 = Rs. 18 lakh
Investment by company B =  Rs. 9 lakh.
For company A,
75 = [p /18 ] × 100.
P= (75 × 18)/ 100 = Rs. 13.5 lakh.
For Company B,
80 = [q / 9] × 100
q = 80 × 9/ 100  lakh
 = Rs. 7.2 lakh
Total profit earned = 13.5 + 7.2 = Rs. 20.7 lakh

3.4) If the incomes of company A in 2007 and 2008 were equal and the amount invested in 2007 was Rs. 12 lakhs, what was the amount invested in 2008?
(a) Rs. 10, 87, 500
(b) Rs. 10, 85, 700
(c ) Rs. 12, 45, 000
(d ) Rs. 12, 85, 000
Sol:
For the year 2007,
45 = (p/12 )× 100
=> p = ( 45 × 12 )/100 = Rs. 5.4 lakh.
Total income  = 12 + 5.4 lakh
=Rs. 17.4 lakh
If the amount invested in 2008 be Rs. 1 lakh, then
60 = [17.4 – I / I] × 100

  • 160 I = 1740
  • I = 1740 /160 = 10.875 lakh
  • = Rs. 1087500.

3.5) If the amount of profit earned by company A in 2006 was Rs. 10.15 lakhs. What was the total investment?
(a) Rs. 13. 8 lakhs
(b) Rs. 14.9 lakhs
(c ) Rs. 15.4 lakhs
(d ) Rs. 18.45 lakhs
sol.:
55 = [10.15/ Investment (I) ] ×100
I = 10.15 × 100/ 55
= Rs. 18.45 lakh.



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