# Data Interpretation Questions with Solutions for Bank PO pdf

In most of the competitive exams – SSC, IBPS, RRB, and other govt recruitment exams, we often came across different sets of data interpretation questions to test the candidate’s analytical and decision-making skills. So, here we are updating **data interpretation questions with solutions** for bank po pdf. These very helpful for those who are preparing for various competitive exams.

**Data Analysis & Data Interpretation** is an important aspect of almost every competitive exam. Usually, the data is given in the form of tables, bar diagram or pie-chart or line graph and candidates are asked questions that test their ability to analyze the data given

In IBPS Bank Exams, data interpretation questions will be asked on Bar Graphs, Line charts, Pie-charts, mixed graphs, tabular forms, missing data. As per the new pattern, The DI questions appearing in recent exams are based on aptitude topics – time and work, pipes & cisterns, ratio & proportion, time & distance, profit & loss, etc., So, the bank exam aspirants have to keep in mind about new patterns while preparing for bank exams and improve their aptitude skills and learn speed maths tricks, aptitude formulas, data interpretation shortcut tricks, to develop one’s calculation ability and mental ability.

Data interpretation is not much difficult, it’s scoring part in exams if you practice more questions using maths shortcut tricks. **To Solve DI Questions in Less Time. Learn fast calculation tips given below**

## DI Questions with Solutions for Bank Exams – SBI PO, IBPS PO

#### DI Questions Practice SET 1:

##### 1. Analyze the data from below given graph and pie-chart carefully to answer the questions that follow:

1.1) The Total number of employees in organization C is approximately what percent of total no. of employees in organization D?

(1) 147 (2) 279 (3) 312 (4) 207 (5) 183.

Solution:

31/ 15 = 207

Explanation: 100% of 15 = 15

200% of 15 = 30

10% of 15 = 1.5 i.e. 30 + 1 = 200% + 7% (approx.) = 207

Note: By practice we can able to do these calculations without using pen.

1.2) What is the total no. of males in all organization together?

Sol:

Average percentage of males = (30 + 55 + 60 + 40 +25) / 5 = 210 / 5 = 42%

- 42/100 × 35000
- 14700

1.3) What is the total number of males in organization A & C together?

Sol:

(18/ 100 × 30/100 + 31/100 × 60/100) × 35000

=> (540 + 1860) × 3.5

=> 2400 × 3.5

=> 240 × 35

=> 8400

1.4) What is the number of females in organization D?

(1) 3855 (2) 3250 (3) 3300 (4) 3675 (5) None of these

Solution:

15 × 60 × 3.5 = 3150.

#### DI Questions Practice SET 2:

**The Pie chart shows the population of various states in a certain year the total population is 60 lakhs.**

**The Population of Various States in a Certain Year.**

The angles subtended at the center of the circle by different sectors are shown in degrees. The percentage of the total population represented by that sector.

**Total Population = 60, 00,000.**

The table below gives a gender-wise and literacy wise population ratio. Study the pie chart and the table and answer the questions that follow:

State |
Gender RatioMale: Female |
Literacy RatioLiterate: Illiterate |

A |
4: 3 |
9: 4 |

B |
5: 3 |
8: 5 |

C |
3: 2 |
9: 5 |

D |
3: 5 |
7: 3 |

E |
9: 7 |
5: 2 |

F |
3: 1 |
1: 3 |

G |
7: 9 |
2: 1 |

**(2.1) What is the approximate total of literates of States ‘B’ and ‘D’ together?**

(a) 1288835

**(b) 1289538 **

(c) 690462

(d) 694026

(e) None of these.

**Solution:** (literates of B) + (literates of D)

=> [(19 × 8/13) + (14 ×7/10)] × 60, 000.

=> [152 +1274] ×60, 000/130.

=> 1426 ×6000/13.

**= 1289538**

**(2.2) The number of females in ‘A’, ‘C’ and ‘E’ is what percentage of the total population of all the above states (‘A’, ‘B’, ‘C’, ‘D’, ‘E’, ‘F’, ‘G’)?**

(a) 12.91%.

(b) 42.13%

**(c) 21.91% **

(d) 24.13%.

(e) None of these.

**Solution: **

**Convert Degrees into percentage **

Population of A = [82.8/360] ×100 = 23%

Population of C = [61.2/360] ×100 = 17%

Population of E = [43.2/360] ×100 = 12%

Females of A, C & E = [(23 × 3/7) + (17×2/5) + (12 ×7/16)]/100 × 60, 00, 000

**No. of females of A, C & E is what % of total population **

= [(69/7 + 34/5 + 84/16)/100] × 60, 00, 000/60, 00, 000

= [(69×80) + (102×34) + (35×84)/ (560)]/100

= [11928/560] × 100 = **21.91%**

**(2.3) If there be a decrease of 4% in the population of ‘E’ and an increase of 3% in the population of ‘F’, in the next year over the respective population of ‘F’ in the next year will be**

(a) 163:128

(b) 125:101

(c) 123:103

(d) **128:103**

(e) None of these.

**Solution: **

Present population of E = [43.2/360] ×6000000 = 7, 20, 000.

**4% of 720000 = 28, 800.**

Therefore, population of E next year = 7, 20, 000 – 28, 800 = 6, 91, 200

Present population of F = 9% of total population = 60, 00, 000 × 9/100 = 5, 40, 000

**3% of population = 16, 200**.

Therefore, population of F next year = 5, 40, 000 + 16, 200 = 5, 56, 200.

Therefore, Ratio of the population of E to the population of F next year

= 691200: 556200

**= 128: 103 (approx.)**

**(2.4) The number of females in state F is approximately what percentage of the number of females in state ‘G’?**

**(a) 66.67%.**

(b) 69.83%.

(c) 76.66%.

(d) 60.67%.

(e) None of these.

**Solution: **

** **The population of State F = 9% of the total population = 5, 40, 000.

= 9% of the total population = 5, 40, 000.

Therefore, number of females in State F = 540000 × 1/ 4.

= 1, 35, 000.

The population of Stage G

= 6% of the total population = 3, 60, 000

Therefore, number of females in stage G = 3, 60, 000 × 9/16 = 2, 02, 500.

Therefore, number of females in State F = ((135000/ 202500) × 100)

**= 66.67%**

**(2.5) If 68.8% of the females and 72% of the males are literate in state ‘D’, then the ratio of male literates to female literates in that state is,**

(a) 109: 329

(b) **189: 301**

(c) 131: 301

(d) 103: 329

(e) None of these.

**Solution:** Population of State D = 14% of the total population = 8, 40, 000

Male: Female ratio is 3:5

Therefore, number of males = 840000 × 3/8 = 3, 15, 000

Therefore, number of females = 840000 × 5/8 = 5, 25, 000

72% of males is 2, 26,800.

68.8% of females are 3, 61,200.

Therefore, the ratio of male literates to female literates is **226800:361200 or**

** 189: 301.**

**(2.6) What is the ratio of the illiterates of State ‘A’ to those of State ‘G’ approximately?**

**(a) ****177: 50.**

(b) 137: 65

(c) 183: 71

(d) 127: 73

(e) None of these.

**Explanation:**

Population of State A = 13, 80, 000.

Therefore, illiterates in State A

= 1380000 × 4/13 = 4, 24, 615.

Population of State G = 3, 60, 000

Therefore, illiterates in State G

360000 × 1/3 = 1, 20, 000

Illiterates in State A: Illiterates in State G =** 177:50 (approx.)**

#### Data Interpretation Questions Practice SET 3:

**3. Study the following chart to answer the questions given below:**

Villages |
% Population below the poverty line |

A | 45 |

B | 52 |

C | 38 |

D | 58 |

E | 46 |

F | 49 |

G | 51 |

3.1) In 1996, the population of villages A, as well as B, is increased by 10% from the year 1995. If the population of village A in 1995 was 5000 and the percentage of the population below the poverty line in 1996 remains the same as in 1995. Find approximately the population of village B below the poverty line in 1996.

(a) 4000

(b) 45000

(c) 2500

**(d) 3500**

Solution: Population of Village B in 1995 = 5000 * (16/13) = 6150.

Population of village B in 1996 = 6150 * (110/100) = 6750

Population below poverty line = 52% of 6750 = 3500(approx)

3.2) If in 1997 the population of village D is increased by 10% and the population of Village G is reduced by 5% from 1995 and the population of Village G in 1995 was 9000. What is the total population of villages D and G in 1997?

**(a) 19770**

(b) 19200

(c) 18770

(d) 19870

**Ans.:** Population of village D in 1995 = 9000 (17/15 ) = 10,200.

The Population of village D in 1997 = 10,200 (110/100) = 11220

Population of village G in 1997 = 9000 * 95/100 = 8550.

Total population of village D and G in 1997 = 11220 + 8550 = 19770.

3.3) If in 1995 the population of 7 villages together was 55000 approximately, what will be a population of village F in that year below the poverty line?

(a) 3000

(b) 2500

(C) 4000

**(d) 3500**

**Solution:** Population of village F below poverty line = 55000 * 13/100 * 49/100 = 3500.

3.4) If the population of village C below the poverty line in 1995 was 1520, what was the population of village F in 1995?

(a) 4000

(b) 6000

**(c) 6500**

(d) 4800

**Solution:** Population of village F in 1995 = 1520 * 100/38 * 13/8 = 6500.

3.5) The population of village C is 2000 in 1995. What will be the ratio of the population of Village C below the poverty line to that of the village E below the poverty line in that year?

(a) 207: 76

**(b) 76: 207**

(c) 152: 207

(d) Data Inadequate.

Solution: 2000 * (38/100) : 2000/8 * 18 * (46/100)

= 760 : 2070

= 76 : 207

#### DI Questions Practice SET 4:

**4. Study the following pie-chart carefully to answer the given questions**

Percentage of Students Who are Studying

Different Specializations in a Management Institute.

The total number of Students = 4500.

The ratio of men to women in each Specialization.

Specialization |
Men |
Women |

HR | 2 | 3 |

Marketing | 7 | 5 |

International Business | 5 | 1 |

Banking | 17 | 10 |

IT | 1 | 2 |

Finance | 5 | 4 |

**4.1) What is the total number of men studying in the Institute?**

(a) 1665

**(b) 2421**

(c) 2025

(d) 1954

**Solution:** First we have to calculate men and women from the pie chart and table for each specialization. It becomes easy to answer other questions also.

Specialization |
Men |
Women |
Total |

HR | 396 | 594 | 990 |

Marketing | 720 | 420 | 720 |

International Business | 675 | 135 | 810 |

Banking | 340 | 200 | 540 |

IT | 315 | 630 | 945 |

Finance | 275 | 220 | 495 |

2421 |
2079 |
4500 |

Number of students in HR

Number of men in HR = 2/5 ×22/100 ×4500 = 2×22×9 = 396.

The number of women in HR = 3/5 ×22/100 ×4500 =594. (This way we have to calculate for each specialization).

From the above, the answer is 2421.

**4.2) The number of women studying marketing is approximately what percent of the total number of students in the institute?**

**(a) 5 (b) 12 (c) 15 (d) 7**

**Solution: **The required percentage is (300×100)/4500 = 6.6% = 7%.

**4.3) What is the total number of men studying Banking and International Business?**

(a) 1125

(b) 297

(c) 1015

(d) 594

**Solution:** The required number of men = 675 + 340 =1015.

**4.4). The number of women studying finance is what percent of the number of men studying the same?**

(a) 80

(b) 65

(c) 95

(d) 70

**Solution:** The required percentage = (220×100)/275.

4.5). In which specialization do the maximum number of women study?

(a) IT

(b) Marketing

(c) HR

(d) Finance.

**Solution:** From the above-solved table. The obvious answer is IT.

#### DI Questions Practice SET 5:

#### Directions (1 to 5 Questions): Study the following graph and answer the questions.

**5.1) What is the total (approx) number of cars sold in the year 2013 if the growth rate in the total number of cars sold from 2012 to 2013 was the same as that of 2011 to 2012?**

**(a) 23905**

(b) 210978

(c) 24189.

(4) 26623

(5) 24659

**Solution:** Clue: Increase in the number of sales from 2012 to 2013 is same as 2011 to 2012

Increase in sales from 2011 to 2012 = 21568 – 19231 =2337.

Increase in sales from 2012 to 2013 is 2337

Therefore, Sales in 2013 = 21568 + 2337 = **23905**

**5.2) In which of the following years the ratio of the number of Maruti cars sold to the total number of cars sold was lowest?**

(a) 2011

**(b) 2006**

(c) 2009

(d) 2008

(e) 2010

* Trick:* Use approximations and guesswork for this question to save time

2006 -> 115: 27 => 11:3 ( In 2006, no. of manufacturing cars sold Maruti cars is lowest compared to other years).

2007 -> 126: 33 => 42: 11= 4: 1

2008 -> 140: 45 => 28: 9

2009 -> 150: 60 => 5: 2

2010 -> 170: 68

2011 -> 190: 70 => 19: 7

2012 -> 215: 99 =>2: 1

**5.3) What was the approximate average number of cars sold (other than Maruti Cars) in a year, taking the data of all the years together?**

(a) 11231

(b) 10317

(c) 10919

**(d) 8778**

(e) 12117

**Explanation: **

**Sale of Cars Other than Maruthi Cars = Total car sales – Maruthi Car sales **

**8826** ** | 9299 | 9410 | 9313 | 10309 | 12031 | 11668**

Average = (8826 + 9299 + 9410 + 9313 + 10309 + 12031 +11668)/ 7 = 61446/7 = 8778

**5.4) The number of Maruthi cars sold in the years 2007, 2008 and 2009 is approximate what percent of the total number of all the cars sold in the years 2006, 2007, 2009, 2011 and 2012?**

(a) 22%

(b) 25%

**(c) 17%**

(d) 29%

(e) 11%

**Solution:** Total no. of car sales (including Maruti cars) in **2006, 2007, 2009, 2011 and 2012 = (11526 + 12649 + 15313 + 19231 + 21568) = 80287.**

Number of Maruthi cars sold in the years** 2007, 2008 and 2009 = 13900.**

Required Percentage = [13900/80287] * 100 =** 17%**

**5.5) What is the ratio between the number of cars sold other than that of Maruti in 2011 to the total number of cars sold in 2006?**

(a) 10: 26

(b) 10: 17

(c) 11: 4

**(d) 11: 8**

**Solution: **

Cars sold other than Maruthi cars in 2011 = (19231 -7200) = ** 12031**

Cars sold other than Maruthi cars in 2006 = (11526 -2700) = 8826

Required Ratio = 12031 : 8826 =12000 : 8800 = 121 : 88 = 11: 8 (approximate)

#### READ ALSO Data Interpretation Shortcut Tricks