# Line Graph Questions – Data Interpretation for Bank Exams

The line graph is nothing but representing the data in the x & y-axis. We need to analyze the given data and have to answer the questions. Solve the below line graph questions using data interpretation shortcut tricks to save time in competitive exams. We also provided the solutions for the below questions, recheck your answers after solving on your own. Here, we are updating the line graph data interpretation questions with solutions for bank exams based on previous question papers.

**Data Interpretation** is a very important topic for SBI and IBPS PO Exams. We need to learn some shortcut methods in adding, subtracting, multiplication and speed maths tricks on some Quantitative aptitude topics to solve Data Interpretation questions in less time.

**Directions: S**tudy the following graphs carefully and answer the following questions given below in each graph.

### I. DI Questions **– SET I:**

**Number of candidates (boys and girls) appeared and qualified in an examination over the years**

**(1.1) What was the approximate percentage of boys qualified to appeared in 1992?**

(A) 35 ** (B) 70 ** (C) 80 (D) 65

** ****Solution: ( B)**

The approximate percentage of boys qualified to appear in 1992.

=12.5/17.5 × 100=71.43 = **70%**

**(1.2) The total number of girls qualified in 1991 and 1992 together was exactly equal to the number of girls appeared in which of the following year**s—

(A) 1994 (B) 1995 (C) 1991 **(D) 1990** (E) None of these

**Solution: (d) **

The total number of girls qualified to appear in 1991 and 92.

=2500+5000= 7500

= Total number of girls involved is 1990

**(1.3) What was the percentage increase in the number of boys qualified from 1993 to 1994?**

(A) 50 (B) 5 (C) 100 ** (D) 200 ** (E) None of these

**Solution: (d) **

The percentage increase in the number of boys qualified from 1993 to 1994

= (15 – 5) * 1000=10000

Percentage increase = 10000/5000* 100 **= 200**

**(1.4) What did the difference between the total number of boys and girls appeared in 1993 and the total number of boys and girls appear in 1991?**

(A) 500 ** (B) 2500 ** (C) 7500 (D) 10000 (E) None of these

**Solution: (b) **

difference between the total number of boys and girls appeared is 1993 and the total number of boys and girls appeared is 1993 and the total number of boys and girls appeared in 1991

= [(12.5 + 10) – (15 + 5)] * 1000

= (22.5 – 20) * 1000= 2.5* 1000

**= 2500**

**(1.5) In which of the following year was the percentage of girls qualified to appear the highest among the given years?**

(A) 1991 **(B) 1993 ** (C) 1994 (D) 1992 (E) None of these

**Solution: (b) **

The percentage of girls qualified to appear in 1990 = 5.0/7.5×100 = 66.66%

The percentage of girls qualified to appear in 1991 = 2.5/5×100 = 50%

The percentage of girls qualified to appear in 1992 = 5/10×100 = 50%

The percentage of girls qualified to appear in 1993 = 7.5/10×100 = 75%

The percentage of girls qualified to appear in 1995 = 7.5/12.5×100 = 60%

The percentage of girls qualified to appear in 1996 = 12.5/17.5×100 = 71.43%

## Line graph Data Interpretation Questions in Bank Exams

### DI Questions **– SET ****II:**

**Percentage profit earned by two companies over the given years.**

**% Profit = [(Income –Expenditure)/ Expenditure]*100.**

** **

** 2.1 ) If the expenditure of company B in 2008 was Rs.200 crores. What was the income?**

**240 Crores**- 220 Crores
- 160 Crores
- Cannot be determined
- None of these.

Let the income be Rs. X Crores.

20 = [(x-200)/200] × 100

- 40 = x-200
- X=
**Rs. 240 crores.**

**2.2) If the income of Company A in 2010 was Rs.600 crores, what was its expenditure?**

- 360 crores.
- 480 Crores.
**375 Crores.**- Cannot be determined
- None of these

The income of Company A in 2002 is Rs. 600 crores and % profit = 60

Assume expenditure is x.

60 = [(600 – x)/x] ×100

x= [(600 – x)/ 60 ] × 100

3x = 3000 – 5x

8x = 3000

X = **Rs. 375 Crores**

**2.3) If the income of company B in 2006 was Rs.200 crores. What was its profit in 2007?**

- 21.5 Crores
- 153 Crores
- 46.15 Crores
**Cannot be determined (income and expenditure not given in 2007)**- None of these.

**2.4) If the income of the two companies in 2006 were equal, what was the ratio of their expenditure?**

- 1: 2
- 26: 27
- 100:67
- Can’t solve
- None of these.

**Company A, 35 = [(I – Exp1)/Exp1 ] × 100 -> (1)**

35Exp1 = 100 I – 100 Exp1

135 Exp1 = 100 I

**Company B, 30 = [(I – Exp2)/Exp2 ] × 100 **

**130 Exp2 = 100 I -> (2)**

From (1) and (2)

135 Exp1 = 130 Exp2

Exp1/Exp2 = 130/135

Ratio of Expenditures of A and B ,

Exp1: Exp2 = 130 : 135

**26: 27.**

**2.5) What is the percent increase in percent profit for company B from the year 2008 to 2009?**

- 75
- 175
- 86
- Cannot be determined

= [(35- 20)/ 20 ] × 100 = **75**

### I. DI Questions **– SET III:**

**Percent profit earned by two companies producing Electronic Goods over the years.**

**Profit Earned = Total Income – Total Investment in the year.**

**3.1) If the profit earned in 2006 by company B was Rs. 812500. What was the total income of the company in that year?**

(a) Rs. 12, 50, 000

**(b) Rs. 20, 62, 500**

(c ) Rs. 16, 50, 000

(d ) Rs. 18, 25, 000

**Sol: **

% profit = [profit earned / total investment ] × 100

65 = [812500/ 1 ] × 100

I = (812500 × 100)/65

= Rs. 1250000

Total Income = Profit earned + total investment.

= Rs. (812500 + 1250000)

**= Rs. 2062500**

**3.2) If the amount invested by two companies in 2005 was equal, what was the ratio between the total income in 2005 of the companies A and B respectively?**

(a) 31: 33

(b) 33: 31

**(c ) 34: 31**

(d ) 14: 11

**Sol: **

70 = (x/ I) × 100

- 70 I = 100x —–à (1)

55 = (y/ I) × 100

- 55 I = 100y —–à (2)

From (1) & (2 )

[70 I /100 ] +I : [ 55 I/ 100] +I

170 I : 155 I = **34 : 31.**

**3.3) If the total income invested by two companies in 2009 was Rs. 27 lakhs while the amount invested by company B was 50% of the amount invested by company A. What was the total profit earned by the two companies together?**

(a) Rs. 21.15 lakhs

**(b) Rs. 20.70 lakhs**

(c ) Rs. 18.70 lakhs

(d ) Rs. 20.15 lakhs

**Sol.: **

Investment by company A = [2/3] × 27 = Rs. 18 lakh

Investment by company B = Rs. 9 lakh.

For company A,

75 = [p /18 ] × 100.

P= (75 × 18)/ 100 = Rs. 13.5 lakh.

For Company B,

80 = [q / 9] × 100

q = 80 × 9/ 100 lakh

= Rs. 7.2 lakh

Total profit earned = 13.5 + 7.2 = **Rs. 20.7 lakh**

**3.4) If the incomes of company A in 2007 and 2008 were equal and the amount invested in 2007 was Rs. 12 lakhs, what was the amount invested in 2008?**

**(a) Rs. 10, 87, 500**

(b) Rs. 10, 85, 700

(c ) Rs. 12, 45, 000

(d ) Rs. 12, 85, 000

**Sol:**

For the year 2007,

45 = (p/12 )× 100

=> p = ( 45 × 12 )/100 = Rs. 5.4 lakh.

Total income = 12 + 5.4 lakh

=Rs. 17.4 lakh

If the amount invested in 2008 be Rs. 1 lakh, then

60 = [17.4 – I / I] × 100

- 160 I = 1740
- I = 1740 /160 = 10.875 lakh
- =
**Rs. 1087500.**

**3.5) If the amount of profit earned by company A in 2006 was Rs. 10.15 lakhs. What was the total investment?**

(a) Rs. 13. 8 lakhs

(b) Rs. 14.9 lakhs

(c ) Rs. 15.4 lakhs

**(d ) Rs. 18.45 lakhs**

**sol.:**

55 = [10.15/ Investment (I) ] ×100

I = 10.15 × 100/ 55

**= Rs. 18.45 lakh.**

### DI Questions **– SET IV:**

**4. Study the following graph carefully to answer the questions that follow.**

4.1) Sales in the year 2001 for company A forms what percent of total sales of company A for all the years together? (rounded off to two decimal points).

**(a) 19.64.**

(b) 18.30

(c) 22.46

(d) 24.19

Sol.: Required Percentage = (1100 * 100)/ 5600 = 19.64.

4.2) Which of the following combinations of year and percentage rise in sales from the previous year for Company A is correct?

(Percentage rounded off to two decimal points)

(a) 2000 – 99.85

**(b) 2001 – 83.33**

(c) 1998 – 43.21

(d) 2003 – 7.68

Sol.: (b).

4.3) Total sales of company B for the years 1997, 1998 and 2001 together is what percent of the total sales of company A is correct?

( Percentage rounded off to two decimal points)

(a) 24.37

(b) 35.64

**(c) 28.81**

(d) 37.29

Sol.: The required percentage = [ (700 + 400 + 600)/5900] * 100 = 1700/59 = 28.81

4.4) What is the ratio of total sales of Company A to the total sales of company B over the years?

(a) 26: 29

(b) 27: 31

(c) 53: 51

**(d) 56: 59**

Sol.: 5600: 5900 = 56: 59

4.5) During which year was the percentage rise/fall in sales from the previous year the highest for company A?

**(a) 1999**

(b) 2001

(c) 1998

(d) 2000

Ans. : (a). It is obvious from observing the graph.

### I. DI Questions **– SET V:**

**5. Study the following graph carefully and answer the questions given below it.**

Maximum Marks |
|||||

Physics |
Chemistry |
English |
History |
Geography |
Hindi |

200 | 200 | 200 | 150 | 150 | 150 |

5.1) Marks obtained by student B in Hindi was what percentage of the marks obtained by student B in Physics?

(a) 25

(b) 150

(c) 125

**(d) 115.38**

**Solution:** Required Percentage = (150/130) * 100

= 115.38%

**5.2) Approximately what was the average percentage of marks obtained by** A in** all the subjects?**

**(A) 70**

(b) 60

(c) 80

(d) 85

**Answer:**

Percentage of marks in English = (70/200) *100 = 35

Percentage of marks in Geography = (110/150) * 100 = 73.

Percentage of marks in Physics = (120/200) * 100 = 60.

Percentage of marks in History = (140/150) * 100 = 93.

Percentage of marks in Hindi = (120/150) * 100 = 80.

Percentage of marks in Chemistry = (160/200) * 100 = 80.

Average % percent of marks = 421/6 =** 70.**

5.3) Approximately what was the average marks obtained by B in Geography, history, and Hindi?

(a) 120

(b) 80

(c) 140

(d) 110

**Solution:** Marks obtained by B in Geography, History, and Hindi

= 100 + 110 +150 = 360/3 = 120.

5.4) In how many subjects did student B obtain more than 70 percent of marks?

(a) 1

(b) 2

**(c) 3**

(d) 4

5.5) What was the difference in the percentage of marks between A and B in History?

(a) 30

(b) 25

(c) 45

(D)** 20**

**Solution:** Difference of % of marks between A and B in History = [(140-110)/150]*100=**20%**

### Data Interpretation Shortcuts and Practice Problems

### DI Questions **– SET VI:**

6. The following line graph shows the profit earned (in the Rs. Cr) by two companies ‘A’ and ‘B’ during six years. Answer the following questions based on the graph.

6.1) What is the ratio of profit earned by Company ‘A’ in 2000 to the profit earned by Company ‘B’ in the year 2005?

(a) 1:1

(b) 1:2

**(c) 2:1**

(d) 3:2

(e) 2:3

Ratio = 40:20 = 2:1

6.2) Profit earned by the company B in the year 2001 is what percent of the profit earned by Company A in 2003?

(a) 25%

(b) 30%

(c) 60%

(d) 75%

**(e) 80%**

= (60/75) * 100 = **80%**

6.3) What is the average profit earned (in Rs.) by company B during the period of 2001 to 2005?

(a) 36 crore

(b) 40 crore

**(c) 42 crore**

(d) 45 crore

(e) 56 crore

Average = (60+ 40+ 40 + 50+ 20)/5 = 210/5 = 42.

6.4) Profit earned by CompanyB in the year 2004 is how much percentage more than that by Company A in the year 2000?

(a) 20%

**(b) 25%**

(c) 40%

(d) 10%

(e) 75%

Percentage = (50 -40)/40 * 100 = 25%.

6.5) What is the percentage rise of profit earned by company B from the year 2000 to the year 2001 ?

(a) 10%

**(b) 20%**

(c) 25%

(d) 40%

(e) 50%

Percentage Rise = (60 – 50)/50 * 100 = **20%.**

### Line Graph Questions **– SET VII:**

#### 7. Study the following graph carefully and answer the questions given below.

**Company A**= **Green,** Company **B** = **Red**,** Company C=** **Blue.**

**(7.1) In which of the following years, the importance of company A was exactly equal to average made by over the given years?**

(a) 1992

(b) 1993

(c) 1994

(d) 1995

(e) None of these.

**Solution:**

Average imports made by company A = (30+50+60+40+70+60+75)/7=385/7=55

In none of the given years, the imports are exactly equal to 55 (crores).

Hence the answer is** (e).**

**(7.2) In which of the following years was the difference between the imports made by company B and C the maximum?**

(a) 1995

(b) 1994

(c) 1991

**(d) 1993**

(e) None of these.

**Answer:** By visual inspection, it is clear that** 1993 i**s the desired year (as the distance between two points is the maximum in 1993.)

**(7.3) In which of the following years were the imports made by the company ‘A’ exactly half of the total imports made by company B and C together in that year?**

**(a) 1992 only**

(b) 1993 only

(c) 1992 and 1993

(d) 1995 only

(e) None of these.

**Explanation: **

By mental observation ( as 50 = 40+60/2). **1992** only is the desired year. You don’t need any calculation. See the year where the point of A lies exactly in the middle of points of B and C.

**(7.4) What was the percentage increase in Imports by company B from 1992 to 1993?**

(a) 10

**(b) 25**

(c) 40

(d) 20

(e) None of these.

**Solution:** percentage increase = [(final -initial) /initial ]* 100

=[50 – 40/40]* 100 = **25%.**

**(7.5) In which of the following years were the total imports made by all the three companies together with the maximum?**

(a) 1996 only

(b) 1997 only

**(c) 1995 only**

(d) 1995 and 1997 only

(e) None of these.

**Solution:** the total imports (in crores) made by all the three companies together: From the heights of the points we observe that the total heights of three points are the maximum withers in 1995, but to be sure we find actual values for the two years.

**In 1995** = 70+80+85 = 235. In 1997 = 75+79+85 =230.**1995** is the desired year

### Line Graph Questions **– SET VIII:**

#### 8. Data given below are regarding the number of students who have appeared/passed in a certification exam from five schools in the year 2005.

**8.1) The number of students who appeared for the exam from school D was what percent more than that who appeared from school B?**

- 50
- 30
**20**- 10
- 25.

**Solution:**

No. of Students appeared from school D = 180

No. of Students appeared from school B = 150

Required percentage = **[( 180 -150)/ 150 ] * 100**

= 30/150 * 100

= 1/5 * 100 = **20%**

**8.2 ) Out of all the given schools, for which school was the number of students failing at the exam maximum?**

- C
- E
**D**- B
- A

**Solution:** Failed students = Appeared – Passed.

No of students failed

School A = 250 -200 = 50.

School B = 150 – 130 = 20.

School C = 240 -210 = 30.

School D = 180 – 120 =** 60.**

School E = 200 – 150 = 50.

**8.3) In the year 2006, the number the exam from school A was 12% more than that who appeared at the exam from the same school in the previous year, how many students appeared at the exam from school A in 2006?**

- 272
**280**- 254
- 260
- 285.

**Solution: No. of students in school A in 2006 who appeared at the exam= **

(250 ×112) /100 = **280.**

**8.4) What is the respective ratio between the total number of students who appeared at the exam from school C and E together and who passed the exam from the same schools together?**

- 11:7
- 13:9
- 11:8
**11:9**- 4:3

Solution: (240 + 200): (210 + 150) = 440:360 =11: 9

**8.5) What is the average number of students who passed the exam from schools A, B, and C?**

- 190
- 160
**180**- 150
- 140

**Solution: **

Average number of students who passed from schools A, B and C = (200 +130 + 210 )/3 = 540/3

**=180**