**Multiplication Tricks for Bank Exams:**

### I. Multiplication of two digit numbers which are having the same number in 10’s place and 5 in its units place.

**1) 25 × 25** = (2× 3)25 = 6__25__.

Understand the logic behind this so that you can able to solve for big numbers.

First, we have to write 25 at the right end as shown above. Then multiply 2 with next biggest number i.e. 3 that is equal to 6. Write this 6 at left end. The answer is 625.

**2) 45 × 45** = (4×5)25 = 2025.

**3) 55 × 55** = (5 × 6)25 = 3025.

**3) 85 × 85** = (8 × 9)25= 7225.

**4) 95 × 95** = (9 ×10) 25= 9025.

### II. Multiplication of 2 digit numbers whose difference is 10 and have 5 at units place.

**1)25×35** = (2 × 4)__75__ = 8__75__.

**Explanation:** Here we have to write 75 at the right end. Then multiply 2 with 4 and write the result at left end as shown above.

**2) 35 × 45** = (3×5)__75__ = 1575.

**3) 45 × 55** = (4 × 6)__75__ = 2475.

**4) 65 × 75** = (6 × 8)75 = 4875.

**5) 85 × 95** = (8 × 10)75 = 8075.

### III. Multiplication of two digit numbers having the same number at 10’s place and the sum of unit’s place digits is 10.

**1) 33 × 37= (3 × 4) 21= 1221.**

__Explanation:__

1) Multiply the last 2 digits at unit’s place 3 and 7 it becomes 21 write this at the right side end.

2) Multiply 3 with next number 4 it becomes 12 then write this at the left side end.

**2) 44 × 46** = (4 × 5) 24= 2024. (Here, 6 × 4 =24, 4 × 5= 20)

**3) 36 × 34** = (3 × 4)24 = 1224.

**4) 52 × 58** = (5 ×6)16 = 3016.

**5) 71 × 79** = (7 × 8)9 = 5609.

**6) 87 × 83** = (8 × 9)21 = 7221.

### IV Multiplication of two digit numbers that have 9 at the 10’s place and the sum of digits at unit’s place should be 5 or 10.

**1)92 × 93**= (92-7) (8 × 7) = 8556

**2)93 × 97**= (93-3) (7 × 3) = 9021

**3) 95 × 95**= (95 – 5) (5× 4) = 9020.

**4) 96 × 94**= (94 – 4) (6 × 4) = 9024.

**5) 91 × 94**= (91-1) (1 × 4) = 9004.

**V. Multiplication using Split & Merge Method:**

**1. 42 × 49 **= 42 (50-1)

= 42 × 50 – 42 × 1. (Here use multiplication trick with 5).

= 2100 – 42.

**2. 25 × 29 = **25 ( 30 – 1).

= 750 -25.

= 725.

**3. 15 × 19 =** 15 (20 -1)

= 300 -15.

= 275.

**VI. Horizontal Multiplication Method:**

**1. 43 × 23 = 8 _ 9.**

(i) we get 8 by multiplying **4 × 2 **and place it at first place.

(ii) Multiply unit’s digits and place it right i.e. **3 × 3 =9.**

(iii) Middle term = (**4 × 3) + (3 × 2) = 12 + 6 = 18.**

= 8 18 9.** = 989.**

**2. 26 × 21 = 4 _ 6.**

(i) 2 ×

**2 = 4 . (1st term)**

(ii) 6

**× 1 = 6. ( last )**

(iii) (2

**× 1) + 6 × 2) = 2 + 12 = 14. (middle). (if there is double digit in middle carry forward to first digit).**

Therefore, we get

**4 14 6. = 546.**

**VI. If the numbers are in **a^{2 }– b^{2 } form ( a^{2 }– b^{2 } = (a+b) (a-b)).

**1. 37 × 43 = (40 -3) (40+3) **

= 1600 -9.

= 1591.

**2. 52 × 48 = (50 + 2) (50 -2) **

= 2500 -4 = 2496.

**VII. Maths Tricks to Multiply any numbers with 5.**

**1. 38 × 5 **

(1) divide 38 by 2 and place 1 zero at the end.

= 38/2 = 190.

**2. 46 × 5 **

Here divide 46 by 2 and place zero at the end.

= 46/2 = 230.

**3. 47 × 5**

(i) divide 47 by 2 and place 5 for odd numbers (47 is the odd number) at the end.

47/2 = 235.

**4. 568 × 5**

(1) divide 568 by 2 and place ‘0’ at the end as 568 is an even number.

568/2 = 2840.

**5. 577 × 5. **

577 / 2 = 2885.

**VIII. Maths Tricks to Multiply any numbers with 25.**

1. 56 × 25 = 56/4 + 00 = 1400.

2. 66 × 25 = 66/4 + 00 = 1650.

3. 788 × 25 = 788 /4 +00 = 19700.

**IX. Maths Tricks to Multiply any numbers with 125.**

Divide the given number by 8 and add 000 at the end.

- 56 × 125 = 56/8 + 000 = 7000.

2. 896 ×125 = 896/8 + 000 = 112000.

**(OR) Check Below**

**IX. Maths Tricks to Multiply any numbers with **5^{n}**.**

**Example :** 974365 × 5^{4 }

= 9743650000 / 2^{4}

**1. 75 × 5 ^{3}**

= 75000/2

^{3 }

**= 9375.**

**2. 88 × 5 ^{2}**

= 8800/2

^{2 }

=

**2200.**

### Some Other Useful Maths Formulae for Bank Exams

1. 2.3 + 3.4 + 4.5 + …….. + n = [n(n^{2 }+6n + 11)]/3 .

2. 1/1.3 + 1/3.5 + 1/5.7 + ………. + 1/ (2n+1) (2n-1) = n/(2n+1).

3. 1 + 3+5+ ……….+(2n +1) = n^{2.}

4. 2 +4 + 6 + ………….. + 2n = n(n+1).

5. 1 + 2 + 3 + ………..+ n = n(n+1)/2.

6. 1^{2 }+ 2^{2}+3^{2}+ …. +n^{2} = n(n+1)(2n+1)/6.

7. 1^{3 }+ 2^{3}+3^{3}+ …. +n^{3} = [n(n+1)/2]^{2}.