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Quadratic Equation Practice Problems with Answers for Bank Exams Shortcut Tricks
In every bank exam, we are expecting to get 5 questions with the analysis of previous exam papers. By the following procedure , we can able to solve these type of problems in seconds of time. Quadratic Equation Practice Problems with Answers by explaining the solutions with images are given below.
A quadratic equation can be solved either with factorization method and by using formula. Factorization method is the time-consuming method. So if we follow the below procedure we can able to solve these problems in less than 30 seconds.
Directions to solve questions. In each question, one or two equations are provided. By solving two equations and find the values of x andy and find the relation between x and y.
Give answer (1), If x≤y.
Give answer (2), If x>y,
Give answer (3), If x<y,
Give answer (4), If x=y,
Give answer (5), If x≥y.
Quadratic Equation Practice Problems with Answers
I. 2x2 – 3x – 9 = 0.
3y2 + 4y – 7 = 0.
Solution:
Explaination:
Here, The product of ends= 2 ×(-9) = -18.
The middle term (-3) should split in such a way that,
the product of the splitting numbers = -18. Here (-6) × (+3) = (-18).
the sum of the split numbers = -3 i.e. Here (-6 +3 = -3).
From the above solution, we can say x>y and
the answer is (2).
II. x2+ 13x + 40 = 0.
y2 + 7y +12 = 0.
Solution:
Explaination:
Equation 1: Here The product of ends = 1 × 40 =40.
The middle term 13 should have to split in such a way that product should be 40 and sum should be 13.
Equation 2:
product of ends = +12.
Sum = +7
Here, x < y and the answer is (3).
III. x2 – 24x + 144 = 0.
y2 – 26y + 169 = 0.
Solution:
Explanation:
In Equation 1, The product of ends =+144
Split +144 into 2 numbers in such a way that the product of 2 numbers is 144
and the sum should be – 24.
In Equation 2, the product of ends = (1* 169) = 169.
Split -26 into 2 numbers in such a way that
the product of those 2 numbers is 169 i.e. (-13 * -13) and sum is -26 ((-13) + (-13 ))
From the above solution, x= 12, y =13.
= x<y.
the answer is (3).
;
IV. 10x2 – 7x + 1 = 0.
35 y2 – 12y + 1 = 0.
Solution:
In Equation 1, The product of the ends (10*1) =10
and split (-7) into -5 and -2 so that its product is 10 and some of those 2 numbers is (-7).
In Equation 2, The product of the ends (35*1) =35
and split (-12) into -7 and -5 so that its product is 35 and the sum of those 2 numbers is (-12).
Here, x ≥ y and the answer is (5).
Note: If you practice 10 quadratic equations by following the above method, then you can observe the change and can solve the problems in very less time than the earlier usage of normal methods.
